Wrong handling of #x in macro

[danmar]

Example code:

#define bar(x) x % 2
#define foo(x) printf(#x "\n")

foo(bar(3));

gcc output:

printf("bar(3)" "\n");

simplecpp output:

printf("3%2" "\n");

[firewave]

1:
2: 
3: 
4: printf ( "bar(3)" "\n" ) ;